Question

Let R be the region bounded by the lines x=0, y=cube root of x, y=10-x. We create a solid of revolution by revolving R about the line y=-2. Set up an expression with integrals that calculates the volume of the solid using the washer method.

          Let R be the region bounded by the lines x=0, y=cube root of x, y=10-x. We create a solid of revolution by revolving R about the line y=-2. Set up an expression with integrals that calculates the volume of the solid using the washer method.
        
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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Let R be the region bounded by the lines x=0, y=cube root of x, y=10-x. We create a solid of revolution by revolving R about the line y=-2. Set up an expression with integrals that calculates the volume of the solid using the washer method.
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Transcript

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00:01 Okay, so here we got the region defined by f of x equals square root of sine of x, x equals 0 and y equals 1.
00:15 Okay, now we just need to notice that f of x is equal to 1 if x is equal to pi over 2.
00:29 So our volume v obtained rotating this region about the x -axis is an integral from 0 to pi over 2 of f of x squared, which is sine of x, multiplied by pi in the x...
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