Let's investigate a three state quantum system (|1ā©, |2ā©, |3ā©). The Hamiltonian for this system is given by:
H ā [E1 0 A; 0 E0 0; A 0 E1]
In the |1ā© ā [1; 0; 0], |2ā© ā [0; 1; 0], |3ā© ā [0; 0; 1] basis the Hamiltonian is NOT diagonal.
1. Are the state vectors, |1ā©, |2ā©, |3ā©, energy eigenstates? How can you tell?
2. Diagonalize H and find the energy eigenvalues. You should find three distinct values (E1 - ?, E0, and E1 + ?). What is the value of question mark?
3. Sketch an energy level diagram for this system. You can assume E0 < E1 and A < (E1 - E0). What is the ground state, the first excited state, the second excited state?
How much energy would be needed to make the transition between the ground state and the two different excited states?
4. Now that you have found the energy eigenvalues, use those eigenvalues to determine the energy eigenstates in terms of the |1ā©, |2ā©, |3ā© basis. Which eigenstate corresponds to the ground state? The first excited state? The second excited state?