00:01
This problem wants us to solve for the missing parts of the triangle.
00:03
So because i have two matching pieces, i have side a and angle a, i can use law of sines to find, um, one of the other two angles.
00:13
So if i do, um, let's do eight over sine 67 .7 equals, and then let's say i want to find angle b.
00:25
I'm going to do 12 over angle b.
00:29
So now if i, um, plug this in, so sine of sine 67 .7 is 0 .925.
00:49
And now if i cross multiply, so that's eight times angle b equals that decimal times 12 is 11 .1 divided by eight is 1 .38.
01:10
Eight, seven.
01:12
Now to find the angle, um, when i'm given a, um, uh, a decimal, i use sine to the minus one.
01:23
Oops...