Question

Let the function $f$ be defined by $y = f(x)$, where $x$ and $f(x)$ are real numbers. Find $f(2)$, $f(-5)$, $f(k)$, and $f(k^2 - 1)$. $$f(x) = \frac{3}{x - 5}$$ $f(2) = $ $f(-5) = $ $f(k) = $ $f(k^2 - 1) = $

Name: let the function f be defined by y fx where x and fx are real numbers find f2 f 5 fk and fk2 1 fx frac3x 5 f2 f 5 fk fk2 1 05868
Uploaded: 2020-07-10T15:57:21-08:00
Duration: 1 min 17 s
Channel: Vishal Parmar
Description: let the function f be defined by y fx where x and fx are real numbers find f2 f 5 fk and fk2 1 fx frac3x 5 f2 f 5 fk fk2 1 05868

          Let the function $f$ be defined by $y = f(x)$, where $x$ and $f(x)$ are real numbers. Find $f(2)$, $f(-5)$, $f(k)$, and $f(k^2 - 1)$.
$$f(x) = \frac{3}{x - 5}$$
$f(2) = $
$f(-5) = $
$f(k) = $
$f(k^2 - 1) = $

$let the function f be defined by y fx where x and fx are real numbers find f2 f 5 fk and fk2 1 fx frac3x 5 f2 f 5 fk fk2 1 05868$

Added by Michael D.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Vishal Parmar

07/10/2020

Step 1

Step 1: To find $f(2)$, substitute $x = 2$ into the function $f(x) = \frac{3}{x - 5}$: $$f(2) = \frac{3}{2 - 5} = \frac{3}{-3} = -1$$ Show more…

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Let the function $f$ be defined by $y = f(x)$, where $x$ and $f(x)$ are real numbers. Find $f(2)$, $f(-5)$, $f(k)$, and $f(k^2 - 1)$. $$f(x) = \frac{3}{x - 5}$$ $f(2) = $ $f(-5) = $ $f(k) = $ $f(k^2 - 1) = $