Let there be two players in a game, Player 1 and Player 2. Consider a jar containing 3 snakes. 2 of the snakes in the jar are venomous, while the remaining 1 is non-venomous. In the game, both the players have to put their hand in the jar one after the other and pick a snake out. Each snake, if picked out of the jar, will bite the player's hand. The event of picking a venomous snake, or equivalently, a venomous snake's bite will earn the player zero points. On the other hand, the event of picking a non-venomous snake, or equivalently, a non-venomous snake's bite will earn the player one point.
Let X denote Player 1's pick and let Y denote Player 2's pick. Suppose Player 1 is the first to pick out a snake.
The expected value of Player 1's pick is: E(X) =
(Express your answer as a fraction or round your answer to two decimal places.)
The expected value of Player 2's pick is: E(Y) =
(Express your answer as a fraction or round your answer to two decimal places.)
Which of the following statements describes the relationship between E(X) and E(Y) in this example?
A. E(Y) is greater than E(X) as there is a greater possibility that Player 1 picks up a venomous snake.
B. E(X) is greater than E(Y) because Player 1 has an advantage of picking first.
C. E(X) and E(Y) are independent of each other. Their values do not reflect anything about their relationship.
D. E(X) and E(Y) are equal, so the order in which the players pick a snake is irrelevant.