Question

Let $\theta$ be an angle such that $\tan \theta = \frac{4}{3}$ and $\csc \theta < 0$. Find the exact values of $\sin \theta$ and $\cos \theta$.

          Let $\theta$ be an angle such that $\tan \theta = \frac{4}{3}$ and $\csc \theta < 0$.

Find the exact values of $\sin \theta$ and $\cos \theta$.
        
Let θ be an angle such that tanθ = (4)/(3) and cscθ < 0.

Find the exact values of sinθ and cosθ.

Added by Andre L.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Let heta be an angle such that tan heta =(4)/(3) and csc heta <0. Find the exact values of sin heta and cos heta . 4 Let 0 be an angle such that tan 0 : and csc0<0. 3 Find the exact values of sin 0 and cos 0.
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Transcript

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00:01 So we're given that the tangent of 2 theta is equal to negative 4 thirds.
00:07 So we know that 2 theta, in order for this to be negative, that picture -wise, we know that that 2 -theta has to either be in the second quadrant or the fourth quadrant.
00:19 And we're told that 0 is less than theta is less than 90 degrees.
00:24 So if we're dealing with this setting, we know that the double angle that if i double this and multiply everything by two, that really this angle, because of that tangent being negative, that has to be a second quadrant angle.
00:46 And the angle theta will be a first quadrant angle.
00:50 Now, we want to find what the sign of the angle is, and we want to find the cosine of the angle.
00:57 And what i notice is really this angle is half.
01:00 So i want to use my half angle identity, not my double angle identity.
01:04 I want to use my half angle identity.
01:07 So i know that the sign of half of 2 theta, half of 2 theta, kind of thinking of that as x over 2, is equal to plus or minus.
01:25 However, i know what my angle, it has to be a first quarter angle, so that's going to be plus the square root of 1 minus, the cosine of the angle, which is 2 theta over 2.
01:43 And for the cosine, again, the cosine is going to have to be positive, and i'm going to use my half angle formula, and the angle i have is 2 theta over 2, and that's equal to, and it's going to be positive, square root of 1 plus the cosine of the x or the 2 theta over 2.
02:06 So i want to draw a picture of this double angle.
02:10 And like i said, we know that that angle has to be over here.
02:15 And we'll pick a point on the terminal side of the angle and we'll drop it down.
02:19 And we'll say that this side opposite has to be positive four.
02:24 And then the adjacent must be negative three...
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