Question

Let U={a, b, d, e, f, j, m, o, t} A={a, b, d, f, m} B = {b, f, m} Apply DeMorgan's Law 2 to show that $(A\cup B)' = A'\cap B'$. To show that $(A\cup B)' = A'\cap B'$, first find $A\cup B$. $A\cup B =$ (Use a comma to separate answers as needed.) Next, find $A'$ and $B'$. $A' =$ $B' =$ (Use a comma to separate answers as needed.) Therefore, $(A\cup B)' = A'\cap B'$ since the roster form of both sets is (Use a comma to separate answers as needed.)

          Let
U={a, b, d, e, f, j, m, o, t}
A={a, b, d, f, m}
B = {b, f, m}
Apply DeMorgan's Law 2 to show that $(A\cup B)' = A'\cap B'$.
To show that $(A\cup B)' = A'\cap B'$, first find $A\cup B$.
$A\cup B =$
(Use a comma to separate answers as needed.)
Next, find $A'$ and $B'$.
$A' =$
$B' =$
(Use a comma to separate answers as needed.)
Therefore, $(A\cup B)' = A'\cap B'$ since the roster form of both sets is
(Use a comma to separate answers as needed.)

Let
U=a, b, d, e, f, j, m, o, t
A=a, b, d, f, m
B = b, f, m
Apply DeMorgan's Law 2 to show that (A∪ B)' = A'∩ B'.
To show that (A∪ B)' = A'∩ B', first find A∪ B.
A∪ B =
(Use a comma to separate answers as needed.)
Next, find A' and B'.
A' =
B' =
(Use a comma to separate answers as needed.)
Therefore, (A∪ B)' = A'∩ B' since the roster form of both sets is
(Use a comma to separate answers as needed.)

Added by Phillip M.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Rashmi Prakash

Step 1

A'nB = (A' ∩ B')' To find A', we need to find the complement of A. Since U = {a, b, d, e, f, j, m, o, t}, the complement of A would be U - A = {e, j, o, t}. Show more…

Show all steps

Thanks for your feedback!

Let U = {a, b, d, e, f, j, m, o, t} A = {a, b, d, f, m} B = {b, f, m} Apply DeMorgan's Law 2 to show that (AUB) = A'nB. To show that (AUB)' = A'nB, first find AUB: AUB = {a, b, d, f, m} Next, find A and B: A = {a, b, d, f, m} B = {b, f, m} Therefore, (AUB) = A'nB since the roster form of both sets is the same.