Let us try to understand the processes that take place after...

let us try to understand the processes that take place after the switch is closed . note that at any moment in time during the life of our circuit, kirchof''s loop rule holds and is indeed, it is helpful. e-vr-vc=0. where vr is the voltage across the resistor and vc is the voltage across the capcitator. part h, integrate both sides

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00:01 So here in this question we are considering a series circuit which we are given here.

00:05 This is the resistor r.

00:07 Here it is connected.

00:08 Then this resistor is connected to the battery source dmf e.

00:13 Then this resistor is connected to the capacitor c.

00:17 Then here it is the switch.

00:19 Let's say initially the circuit is open.

00:23 So here in this point i naught is equals to zero and here in this point q naught is equals to zero.

00:30 So this process is given.

00:32 So here in the first part of the question we have to answer this in terms of e, c and r.

00:38 We have to find out the value of q where we are given the certain terms that circuit is consisting a resistor capacitor which are connected to a emf source with negligible internal resistor.

00:51 So the charge of the capacitor is basically the current in the circuit and we are given that the kirchhoff's rule holds here.

00:59 Indeed it helps us e minus v of r minus v of c that is equals to zero from here.

01:06 So from here initially the circuit is open.

01:09 So we can say that that the initial charge on the capacitor is zero because the voltage across the capacitor is zero.

01:37 Hence this is the answer to the part a of the question...

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