00:01
I'm going to start let, let me use the hint, let b1 dot -da -dot bk, let that be a basis for u intersect w.
00:28
Now, i'm not going to write now, every linear, really independent, independent set of vectors can be extended to a basis to a basis.
01:06
I'm not going to prove this fact, because there's not a lot of time, but you can take it for granted for the sake of this problem.
01:16
And the way we're going to use this is v1.
01:22
We know that v1bk is linearly independent set.
01:44
In both u and w.
02:01
So led v1 to vk, u1 to u and u and b.
02:12
U1 to u and b basis for u.
02:21
And so all i did here was i took the linearly independent vectors of mu, v1, vk, and i extended it to a basis for u using the additional linearly in the linearly independent effect is you want to un and we do the same thing for w and let v1 to vk w1 to wm be a basis for w now we define the set you plus w to be you plus w those in a lower case such that you is in you and w is in w.
03:21
And so now we will prove v1 to bk, e1 through union, union, v1 through vk, w1 through wm.
03:58
Your problem gives us these two sets names, but i didn't...