00:01
Hi, i'm david and i'm here to have you answer your question.
00:03
Now let me bring up your question here.
00:06
In this question here we're given the drawn density of the x and y.
00:11
And here in the part i will have to find the covariance between x and y.
00:16
If you might be that the covariance of the x y equal to the e of x y minus e of x times e e under y.
00:27
Now let's try to find the e on the xy by formula equal to the double integral for the xy times the density here equal to xy.
00:40
Now the x, dy, x from 0 to the 2, y will be from 0 to 1.
00:47
This one we can separate into the 2 integrals, multiply each other.
00:52
Now x it will be the x square from 0 to 2.
00:56
Y will be the y square from 0 to 1.
01:00
Untie derivative of the x squared equal to x power 3 over 3, it varies from 0 to 2 times untary derivative of y square equal to y square equal to y 2 over 3 is invariant from 0 to 1...