Since X and Y are uniformly distributed in the interval (0, 1), their expectations are:
E[X] = E[Y] = \int_0^1 x dx = \frac{1}{2}
So, E[X + Y] = E[X] + E[Y] = \frac{1}{2} + \frac{1}{2} = 1.
Thus, the expectation E[X + Y] is:
$\boxed{E[X + Y] = 1}$
b)
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