Let X be a normal random variable with mean 15 and standard deviation 5. (a) Calculate P (X> 12). (b) Calculate P (10 <X <25). (c) Find a value c such that P (c - X <= 2) = 0.5.
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Step 1
The z-score is given by: z = (X - μ) / σ where μ is the mean and σ is the standard deviation. Plugging in the values, we get: z = (12 - 15) / 5 = -3/5 = -0.6 Now, we need to find the probability P(Z > -0.6) using the standard normal table or a calculator. We Show more…
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