Question

Let X be the number showing on a fair six-sided die. The distribution of X has mean 3.5 and standard deviation 1.71. If a six-sided die is rolled 30 times, what is the probability that the average of all 30 rolls is greater than 3? What is the probability that the average of all 30 rolls is less than 3?

Name: let x be the number showing on a fair six sided die the distribution of x has mean 35 and standard deviation 171 if a six sided die is rolled 30 times what is the probability that the averag 42536
Uploaded: 2022-03-06T08:24:23-08:00
Duration: 2 min 11 s
Channel: Satpal Satpal
Description: let x be the number showing on a fair six sided die the distribution of x has mean 35 and standard deviation 171 if a six sided die is rolled 30 times what is the probability that the averag 42536

          Let  X  be the number showing on a fair six-sided
die.   The distribution of X has mean 3.5  and
standard deviation 1.71.  
If a six-sided die is rolled 30 times, what is the probability
that the average  of all 30 rolls is
greater than 3? What  is the probability that
the average  of all 30 rolls is less
than 3?

Added by Hailey W.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Satpal Satpal

03/06/2022

Step 1

Given: Mean (μ) = 3.5 Standard Deviation (σ) = 1.71 Sample size (n) = 30 Calculate the z-score: \[ z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}} = \frac{3 - 3.5}{\frac{1.71}{\sqrt{30}}} \] Show more…

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Let X be the number showing on a fair six-sided die. The distribution of X has mean 3.5 and standard deviation 1.71. If a six-sided die is rolled 30 times, what is the probability that the average of all 30 rolls is greater than 3? What is the probability that the average of all 30 rolls is less than 3?