Let z be a standard normal random variable with mean = 0 and standard deviation = 1. Find the percentile. (Round your answer to two decimal places) z or the 85th percentile 0.15 z or the 95th percentile 0.05 z or the 96th percentile 0.04
Added by Christopher N.
Step 1
For the 85th percentile, we want to find the z-score such that the area to the left of the z-score is 0.85. Using a standard normal table or calculator, we find that the z-score is approximately 1.04. So, the 85th percentile is at z = 1.04. Show more…
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