00:01
Hello students in this question you are given the radius of the loop of the roller coaster as 7 .8 meter and mass of the object is given to be 359 kg.
00:16
In the loop we know that centripetal force is given as m v square by r.
00:28
At the top of the loop top of the loop top of the loop this central repeater force is going to be equal to the weight plus the normal.
00:42
At this point, both the weight and the normal force will be acting downwards and n is going to be equal to zero at the top.
00:53
Therefore, fc is equal to weight or m v square by r is equal to m g.
01:05
Therefore from here we can calculate v square which is equal to g r which is equal to 8 .74 meter per second on plugging the values now at top of the loop the energy is equal to potential energy plus the kinetic energy the height out here is twice twice the radius of the loop.
01:40
So this potential energy becomes twice m, g, r and kinetic energy is half m v square.
01:51
At top of the ramp, this energy is nothing but the potential energy at this point, which is nothing but m.
02:04
G...