00:06
First to set up a nice table here, cocl2 gas, equilibrium with co gas and cl2 gas.
00:20
We're told that in this question here, we start with one molar phosphogen, initially in zero of the others.
00:31
The chaita's principle will shift towards the product side, minus plus plus.
00:35
This is a 1 to 1 to 1 more ratio, so minus x plus x and plus x, 1 .0 minus x, x and x.
00:46
The equilibrium expression will be, we're doing the partial pressure, so kp is equal to the partial pressure of co, partial pressure of cl2, divided by the partial pressure of the phosphogein.
01:01
We are told the equilibrium constant which is 6 .8 times 10 to the negative 9 which is equal to substituting our values from the ice table partial pressure of co and cl2 are each x partial pressure of phosphagene is 1 .0 minus x this will yield a quadratic and when we solve i won't do the solution for the quadratic.
01:35
We will get two roots...