Light is incident from air onto the surface of a liquid. The angle of incidence is $53.0^{\circ},$ and the angle of refraction is $34.0^{\circ} .$ At what angle of incidence would the reflected light be 100$\%$ polarized?
Added by Jeffrey W.
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Given: $n_1 = 1$, $\theta_1 = 53.0^\circ$, $\theta_2 = 34.0^\circ$ Using Snell's Law: $n_1 \sin(\theta_1) = n_2 \sin(\theta_2)$ Substitute the values: $1 \times \sin(53.0^\circ) = n_2 \times \sin(34.0^\circ)$ Solve for $n_2$: $n_2 = Show more…
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