\( \lim _{x \rightarrow 0} \frac{\ln (x-2)}{e^{\ln (x-2)}} \)
Added by Olivia C.
Close
Step 1
First, let's simplify the expression inside the limit: \( \ln (x-2) \) can only be defined for \( x > 2 \), so we need to consider the limit as \( x \) approaches 2 from the right side. Show more…
Show all steps
Your feedback will help us improve your experience
Jason Orozco and 78 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate limit. $$\lim _{x \rightarrow e^{2}} \frac{\ln ^{2} x-5 \ln x+6}{\ln x-2}$$
Limits
Continuity
Find the limits: $$ \lim _{x \rightarrow 0}(\ln x-\ln 2 x) $$
$$ \lim _{x \rightarrow e} \frac{\ln x-1}{x-e}\left\{\text { Ans. } \frac{1}{e}\right\} $$
Recommended Textbooks
Precalculus with Limits
Precalculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD