00:01
Hello everyone in this question they have given a reaction that is calcium carbonate react with hcl which gives calcium chloride that is c .cl2 plus water plus along with carbon dioxide gas here they have given the grams of calcium carbonate is how much gram they have given that is 2 .35 gram so similarly they have given number the mass of hcl that is also 2 .35 grams.
00:36
Here they've asked that how many liters of gas is going to produce that is carbon dioxide is produced how many liter of gas is going to be produced so for that we are going to calculate number in first number of modes of calcium carbonate and number of mores of hcl so first now i'm going to start with number of mores of calcium carbonate that is n of c c c .o3 is equal to mass of c c c c .o3 is 2 .35 upon molar mass of c .o3 is 100 and 100 .1.
01:10
So we'll get number of moles is become 0 .0235.
01:15
0 .0 .235 moles.
01:18
Similarly, i'm going to calculate number of moles of scl.
01:21
So that is n of hcl is equal to mass of scl is 2 .35 upon molar mass of hcl is 36 .5.
01:32
Its value becomes 0 .06 double 4 0 .0 6 .4 ml so from this data we can say that here calcium carbonate c.
01:47
C.
01:47
C.
01:47
C .o .3 acts as limiting reagent.
01:54
Why because? why because here number of more of c .a.
02:00
Co3 number of mecl that is n of h .cl is greater than n of c .s.
02:06
Co3.
02:07
So that is why the calcium carbonate act as a limiting reagent...