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7. Project $\begin{pmatrix} k_2 \\ k_3 \end{pmatrix}$ into the line spanned by the vector $\begin{pmatrix} -1 \\ 1 \end{pmatrix}$.

          7. Project $\begin{pmatrix} k_2 \\ k_3 \end{pmatrix}$ into the line spanned by the vector $\begin{pmatrix} -1 \\ 1 \end{pmatrix}$.
        
7. Project < p m a t r i x > into the line spanned by the vector < p m a t r i x >.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Linear Algebra K1 = 1, K2 = 6, K3 = 1, K4 = 4 k2 = 7. Project into the line spanned by the vector 163.
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Transcript

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00:01 Hello, welcome to this lesson.
00:03 In this lesson we are looking for the value of k in a vector 1, k negative 2 for which we have a linear combination of e1 which is 1, 2, 3 and e2 which is 2, 3 and 1.
00:22 All right, so the first thing that we'll do is that we look for scalars a and b such that we can have the vector 1, k and negative 2 represented as the scalar a times the first vector which is 1, 2 and 3 then plus the second vector which is 2, 3 and 1.
00:48 So if there is this scalars a and b such that we can write the vector 1, k negative 2 then actually we can have a value of k such that the vectors e1 and e2 can be written as a linear combination of the vector 1, k negative 2.
01:11 So here if we expand then we would have 1 that is equals to so a times 1 right which is a then 2 times b right which will be 2b so this will be equation 1.
01:38 Then when we go to the second part we have k which is equals to 2 times a times this value then we have 3 times this value so plus 3 b so this is equation 2.
01:55 Then we also have negative 2 which is equals to a times 3 so 3 a then b times 1 so this is plus b that is equals to equation 3...
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