Lineman a has a mass of 140 kg and a velocity of 6 ms...

Lineman A has a mass of 140 kg and a velocity of 6 m/s. Quarterback B has a mass of 90kg and a velocity of 7m/s. Solve for the shared velocity following impact. (Hint: Inelastic collision). Also, why would your value be considered negative?

Transcript

00:01 Here we have two football players so name them as player 1 and player 2 the mass of player 1 m1 is 110 kg and is moving with a velocity v1 equal to 4 .1 meter per second player 1 is moving in the positive x direction that means player 1 is moving towards the right direction then we have player 2 whose mass m 2 is 135 kg and the velocity v2 is negative of 3 .4 meter per second the negative sign here in that the player 2 is moving in the negative x direction or towards left at one point of time they collide and they cling together we have to find out their combined velocity after they cling together we take this velocity to be equal to after collision both the player 1 and player 2 will move with the same velocity which is v now to solve this question we'll have to apply the concept of momentum conservation momentum conservation can be applied because there is no external force that is acting and according to momentum conservation the initial momentum of an object is equal to its final momentum now momentum is given by the mass of the object multiplied by its velocity v so initially the moment of player 1 would be the mass m1 multiplied by the velocity v1 plus the initial moment of of player 2 is the mass m2 multiplied by v2 equal to the final momentum of player 1 which is its mass multiplied by the final velocity is v which is the combined velocity plus the final momentum of player 2 is the mass m2 multiplied by v we now put the known values the mass m1 is 110 kg multiplied by v1 is 4 .1 meter per second plus m2 is 135 kg multiplied by v2 is negative of 3 .4 meter per second equal to we'll have here m1 plus m2 multiplied by v because v is the common term here this gives us minus 8 is equal to m1 is 110 kg plus m2 is 135 kg multiplied by v upon solving this we get the value of v which comes out as negative of 0 .033 meter per second therefore, the combined velocity of the players, that is player 1 and player 2, is 0 .03 meter per second in the negative x direction.

03:09 The negative x direction is known from the negative sign here, which implies that they both move towards the left after collision...

Question

Lineman A has a mass of 140 kg and a velocity of 6 m/s. Quarterback B has a mass of 90kg and a velocity of 7m/s. Solve for the shared velocity following impact. (Hint: Inelastic collision). Also, why would your value be considered negative?

Please give Ace some feedback