00:01
In the given compounds we are going to find out the solubility first for the given salt 1.
00:06
For salt 1 where we have given the salt is h2y and this h2y when get dissociated it will produce 2x positive plus y2 negative.
00:21
The solubility of h2y is taken as s then 2x will be 2s, this will be s.
00:27
So the ksp the solubility product over here will be 2s coer multiplied with s because the solubility product is the x positive concentration to the power 2 y2 negative and here the solubility of x2 x positive is 2s and s is the solubility of cy2 negative that is why here the value of the ksp we will get 4s3.
01:04
So s will be equal to ksp divided by 4 and its root q the solubility product of salt 1 is given 8 .6 times 10 to the power minus 14 divided by 4 root q and the value of the s will get 2 .77 times 10 to the power minus 5.
01:31
This is the solubility of this is the a value of the a which is the solubility of solubility of a2y.
01:43
Here for salt 1 we found the solubility next going to the salt 2, the salt 2 is ab2 and this ab2 get dissociated to produce a2 positive plus 2b negative, the solubility are s, s and 2s.
02:06
So the solubility product will be a multiplied with 2s coer which is 4sq...