0:00
Hello everyone.
00:01
So according to the question, we need to find out over here a rate of heat removal.
00:07
Okay, so that what we need to be find out over here.
00:10
So let us discuss first of all question.
00:13
So question is going to be saying that a long circular aluminum rod is going to be attached at the one end of the heat wall and transfer the heat with by a convention of cold fluid.
00:24
The diameter of the road is going to be triple.
00:27
So how much rate of heat is going to be removed? here that we need to be find out so i would like to draw this particular diagram over here so that from the diagram we will get to know more good way okay just wait a minute i will draw this trying to draw this particular diagram this is how it's going to be applicable this is what this says we are going to be considering as in q okay this is a diameter okay this will be the whole diameter d and this we are going to be saying that as aluminum rod okay fine so let us through the solution part so we can say that the rod or rate of heat removal is proportioned to the area corrected therefore the rate of heat removal should be increased by how many time it should be increased by that nine time so i'm going to be writing up over here the explanation part of the solution so let us begin with the solution part that the explanation for the complete explanation we must assume something now we are going to be assuming a rod used must be must be initially initially sorry infinitely along with long with uniform convention coefficient and having a constant property and having constant properties.
02:32
So that is what we are going to be considering that particular figure, that one we are going to be writing.
02:38
This is one figure from above figure we can say that.
02:42
And b we need to see the other one that we can say it is a steady state condition with a one dimension conduction.
02:53
It is steady state.
02:59
Condition with what with one dimension conduction or we can say the construction c part the k value of aluminum is the k value of or we can say for aluminum is is how much is to 40 w divided by m k okay therefore i would like to write it over here they initially long rod fine okay used for the rate we are going to be using that particular rate as an q r is equal to m is equal to npk a c half cube b where q is equal to how much it's going to become h pi d k by d squared divided by four so it's going to become half and qb where this is nothing but half pi by two divided by two hk one square raised to one divided by two d three divided by two qb where i would like to write the specification over here p is equal to we are going to be considering a pi d and ac we are going to be considering over here pi d square divided by 4 this is what circular cross section circular cross section okay therefore i would like to write therefore q f is correspond to d3 by 2 the diameter of the aluminum pipe is what triple 8 here the diameter of the aluminum pipe is what tripled.
05:20
So that is qf3d divided by how much going to become qfd...