Long problem (18 points) Show all work, clearly indicate...

Long problem (18 points) Show all work, clearly indicate answer, and use correct units for full credit. Look at the configuration of charges below. $Q_1 = 6.00\mu C$ $Q_2 = -8.00 \mu C$ $Q_3 = -2.80 \mu C$ $r_1 = 0.0150m$ $r_2 = 0.0225m$ a) What is the net electric field (magnitude and direction) at point P b) What is the Electric Potential at point P? c) If an -7.50 $\mu C$ charge was placed at point p, what would be the net force (magnitude and direction) that the electron would feel? What Electric Potential Energy would it have?

Transcript

00:01 Hello students, according to part a we are going to find out the electric field at point p is equals to 1 by 4 pi epsilon 0 into q1 divided by r1 square plus q2 divided by r2 square plus q3 divided by r3 whole square.

00:24 Now we have to apply the values 9 into 10 to the power of 9 into 1 into 10 to the power of minus 6 divided by 5 square plus 2 into 10 to the power of minus 6 divided by 4 square plus 3 into 10 to the power of minus 6 divided by 3 square.

00:44 From this we can find out the electric field at point p, electric field at point p is equals to 4485 newton per coulomb, 4485 newton per coulomb.

00:56 Now point b, for b we have to find out the electric potential, electric potential at point b.

01:07 For that we are going to use the formula 1 by 4 pi epsilon 0 into q1 r1 plus q2 r2 plus q3 r3, q3 r3.

01:19 Now we have to apply the values 9 into 10 to the power of 9 into 1 into 10 to the power of minus 6 divided by 5 plus 2 into 10 to the power of minus 6 divided by 4 plus 3 into 10 to the power of minus 6 divided by 3.

01:34 As per this we can find out the total value of electric potential, e dot p, electric potential at point p is equals to 15300 volt.

01:48 Now part c, part c.

01:52 In part c we are going to find out, in part c we are going to find out the electric potential, energy, electric potential energy, electric potential energy of the system, of the system.

02:06 For that we are going to use 1 by, same formula we are going to use 1 by 4 pi epsilon 0, q1 q2 r1 plus q2 q3 plus r2 plus q3 q1 by r3.

02:25 We have to apply the values 9 into 10 to the power of 9 into 2 by 3 plus 3 by 4 plus 6 by 5 into 10 to the power of minus 12.

02:36 From this we get the final value that means the u, electric potential energy is equals to 23 .55 joules.

02:43 This is the answer for part c.

02:45 In part d, in part d we are going to find force on proton, force on proton by q1, q2 and q3.

02:59 Now we have to apply the formula for f1, f1 vector is equals to 10 to the power of minus 6 into 1 .6 into 10 to the power of minus 19 into pi square...

Question

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