Question

A long, thin wire carrying 6.3 nC/m runs down the center of a long, thin-walled pipe with radius 3.0 cm carrying -3.6 nC/m spread uniformly over its surface. Part A Find the electric field 1.5 cm from the wire. Express your answer in kilonewtons per coulomb. E1 = kN/C Part B Find the electric field 4.5 cm from the wire. Express your answer in kilonewtons per coulomb. E2 = kN/C

          A long, thin wire carrying 6.3 nC/m runs down the center of a long, thin-walled pipe with radius 3.0 cm carrying -3.6 nC/m spread uniformly over its surface.

Part A
Find the electric field 1.5 cm from the wire.
Express your answer in kilonewtons per coulomb.
E1 = kN/C

Part B
Find the electric field 4.5 cm from the wire.
Express your answer in kilonewtons per coulomb.
E2 = kN/C

A long, thin wire carrying 6.3 nC/m runs down the center of a long, thin-walled pipe with radius 3.0 cm carrying -3.6 nC/m spread uniformly over its surface.

Part A
Find the electric field 1.5 cm from the wire.
Express your answer in kilonewtons per coulomb.
E1 = kN/C

Part B
Find the electric field 4.5 cm from the wire.
Express your answer in kilonewtons per coulomb.
E2 = kN/C

Added by Monica P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

11/02/2022

Step 1

5 cm from the wire. Given: - Charge density of wire (λ) = 6.3 nC/m = 6.3 x 10^-9 C/m - Distance from wire (r) = 1.5 cm = 1.5 x 10^-2 m Using the formula for electric field due to a wire: \[ E = \frac{\lambda}{2\pi \varepsilon_0 r} \] Show more…

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Long thin wire carrying 6.3 nC/m runs down the center of a long, thin-walled pipe with a radius of 3 cm. The pipe carries 3.6 nC/m spread uniformly over its surface. Part A: Find the electric field 1.5 cm from the wire. Express your answer in kilonewtons per coulomb. Part B: Find the electric field 4.5 cm from the wire. Express your answer in kilonewtons per coulomb.