00:01
Hello, so today i'm going to answer your question about the performance of a battery and a specific application of the cita test for doing so first i sketch the formula for the ceta test that you need to apply here but x is the value that you want to evaluate me is the mean of the population and is this the standard deviation so the first process that you need to do is replace the value so in this case you want to evaluate that 7 .5 so you need to standardize this value how subtracting by the mean and divided by the standard deviation this gives you 1 .25 the standard value and then you need to evaluate what are the chances that ceta is smaller than 1 minus 1 .25 in this case is 10%.
00:40
So it's quite high in case that for example so in this case you can reject down the hypothesis that is that this value is possible.
00:49
They as well would be the mean to have a value of 2 % so in this case i need to isolate this mu but if you were first finding the value of 2%, that is 2 .05 that would be the ceta value then i take this value and put it in the equation.
01:06
Now i need to isolate this mu.
01:08
What i did here was multiply by 0 .4 or the standard deviation on both sides, and then subtract by 7 .5.
01:15
Then i just simply multiply by minus 1 on both sides, and i know that the mu, the mean need to be 6 .68 to have this percentage with 7 .5.
01:25
Then you need to have an application of the uniform distribution.
01:29
So first, the density function is determined by this formula.
01:31
I just replace 4 and 1 that is the hours that is the remitted.
01:36
This would be the height of the function...