0:00
Hello.
00:01
So in this question, let us first draw the lewis structure of all the given compound and then determine the resonance.
00:09
So first compound here it is given that is cs2.
00:12
So the resonance structure for this c double bond s and double bond s and this sulfur atom they have two lone pairs in this case.
00:23
So this cs2 shows the resonance structure as it can be drawn like this.
00:31
This double bond s is there and s is there suppose this positive and one negative one if this double bond gets shift here so then in that case one two three four and five six so therefore negative is there so this shows the this shows the resonance structure next we have that is s -o -2.
01:11
So the resonance structure of s -o -2 is we have this s, double bond o, double bond bond, the bend shape it is.
01:22
So loan pair is there, loan pair is there and loan pair is also there in this case.
01:30
So, so2 shows again the resonating structure, resonance is there as this loan pair can get shift to this oxygen and hence we will have this double one o and o now it will have three lone pair therefore the more electron cloud is there and this will have only positive charge so this is the resonating structure for this here yes this compound it have the resonance structure next we have o3 next molecule is o3 and ozone it is so this is double bond o and this is o.
02:15
Two loan pairs are here and two one loan pairs are there and three loan pairs are present there.
02:22
So this o3 shows the resonating structure.
02:25
Yes and it can be drawn in this way also.
02:32
Loan pair, loan pair is there.
02:34
Now this oxygen will have three loan pair and this will have this.
02:38
So this is the, yes, this shows the resonating structure.
02:43
Next we have pcl3.
02:49
Pcl3.
02:50
Now let us draw first the resonating structure of this molecule as p and 3 chlorine atoms are attached with this.
03:03
And the valence electrons are in this case as this one.
03:08
As there is a sharing of electrons.
03:10
That is why they are forming a bond here.
03:12
So now there is no resonance form in pcl3 because if p form a double bond by the resonance then their octet gets disturbed.
03:23
So therefore there is no resonance in this case.
03:29
Next we have next it is given that is b .c .l3.
03:35
So in the boron chloride, the boron atom in bcl3 has an incomplete octate.
03:42
So the structure is cl, cl and cl it is and electrons are present here...