00:01
Hi, i'm david and i'm to help you answer your question.
00:03
Now let me bring up your question here.
00:06
In the question here we are going to discuss about the sampling distribution on the sample proportion.
00:11
Let me remind you that under certain condition, the p -hard will be approximately to the normal.
00:17
Well, we have the mean motp h equal to the population proportion and we have the standard division on the p -hr sometimes called the standard error.
00:29
It will equal to square root of p times 1 minus b over the n.
00:36
Now in this question here we are given that the p equal to the 25 % and it will equal to the 1725 we're given the standard error of the proportion equal to the zepon 0625.
00:53
Now in the question a asks let you find the same process end.
00:59
Now because the standard error equal to this one, so 0 .0 .06, 25, and by the formula equal to the square root of the p equal to the 0 .25, 1 minus 0 .25, over the n.
01:15
So from here, we can find that the square on both sides, we will have the n.
01:22
It will equal to the 0 .25 times with the z upon 75, divided by the zabon 0 .0.
01:30
0625 square and if we compute it we will get equal to 025 times 075 divided 06 25 square equal to the 48 so n equal to the 48 that will be the answer for the 8 now for the p here we are going to indicate the sample portion on the book in treatment and we have by the formula the p .00 be approximately to the normal that will be with the mean on the pheed equal to the p equal to the zon 25 and the standard division on the p hath equal to the 06, 25.
02:15
And from the question c, once you find the probability that 20 % are more, so will be the p hath will be quite equal to the zabon 2.
02:27
Now to find this probability, i will remind you that it will tend to the p h minus the mean of the standard division we have 10 standard no more.
02:37
So if we use this formula, we will convert that p ht into the z.
02:42
So we will take the 0 .2, we minus the p will be the 0 .25, over the standard division equal to the 0 .625...