Assume that a sample is used to estimate a population proportion \( p \). Find the margin of error M.E. that corresponds to a sample of size 332 with \( 11.1 \% \) successes at a confidence level of \( 80 \% \). M.E. \( = \) \( \% \) Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place Question Help: \( \square \) Video Submit Question
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This is given by the number of successes divided by the sample size. In this case, it's 11.1% or 0.111. Show more…
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