Question

Chapter 3, Problem 3/002 (video solution to similar problem attached) The 32-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 71 N, and (c) P = 163 N. The acceleration is positive if up the slope, negative if down the slope. $\mu_s = 0.18$ $\mu_k = 0.14$ Answers: (a) P = 0 $a = $ $m/s^2$ (b) P = 71 N $a = $ $m/s^2$ (c) P = 163 N $a = $ $m/s^2$

          Chapter 3, Problem 3/002 (video solution to similar problem attached)
The 32-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 71 N, and (c) P = 163 N. The acceleration is positive
if up the slope, negative if down the slope.
$\mu_s = 0.18$
$\mu_k = 0.14$

Answers:
(a) P = 0  $a = $ ____ $m/s^2$
(b) P = 71 N $a = $ ____ $m/s^2$
(c) P = 163 N $a = $ ____ $m/s^2$

Chapter 3, Problem 3/002 (video solution to similar problem attached)
The 32-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 71 N, and (c) P = 163 N. The acceleration is positive
if up the slope, negative if down the slope.
= 0.18
= 0.14

Answers:
(a) P = 0 a = m/s^2
(b) P = 71 N a = m/s^2
(c) P = 163 N a = m/s^2

Added by Michael P.

College Physics: Reasoning and Relationships

Nicholas J. Giordano 2nd Edition

Chapter 8

Instant Answer

Solved by Expert Dwijendra Rao

Step 1

The net force is equal to the applied force minus the force of friction. The force of friction can be calculated using the equation: Frictional force = coefficient of friction * normal force Since the crate is stationary, the normal force is equal to the weight Show more…

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The 32-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 71N and (c) P = 163N. The acceleration is positive if up the slope and negative if down the slope.