00:01
So for this question, we're trying to find out the maximum moles of hydrogen that could be produced when we start out with 2 .65 moles of magnesium and 1 .83 moles of water.
00:13
So first we have to figure out which the limiting reagent is.
00:18
And the limiting reagent is going to tell us the maximum amount of hydrogen that can be produced.
00:25
So first, let's figure out how much hydrogen could be produced if we start out with 2 .65 moles of magnesium.
00:34
So we have our 265 moles of magnesium.
00:39
Now we can compare the molar ratios by looking at the coefficients in the balanced equation.
00:47
So we have one mole of magnesium and one mole of hydrogen.
00:54
So we can say that one mole of hydrogen is produced for every one mole of magnesium that reacts.
01:04
Moul of magnesium on top, cancel out a mole of magnesium on the bottom.
01:07
2 .65 times one, right, is going to be 2 .65 moles of hydrogen.
01:15
So if all of the 2 .65 moles of magnesium react, then it will produce 2 .65 moles of hydrogen...