00:01
The reaction is mg plus 2 hcl will form mgcl2 plus h2 where we will see 1 mole of magnesium reacts with 2 moles of hydrochloric acid hcl to produce 1 mole of mgcl2 and 1 mole of hydrogen h2.
00:42
If we will find out 1 mole of magnesium reacts with 2 moles of hydrochloric acid then 2 .5 moles of magnesium will react with 2 times 2 .5 which is 5 moles of hydrochloric acid.
01:10
The reaction to find out the limiting reagent where the given mass of magnesium is 0 .020 gram and the volume of hydrochloric acid is 10 milliliter and number of moles can be calculated, number of moles of the magnesium can be calculated as mass divided by molar mass.
01:44
So, here the mass is 0 .020 gram, molar mass of the magnesium is 24 .3 gram per mole.
01:53
So, number of moles of magnesium is equal to 0 .00082 moles.
02:01
We know density rho is equal to m divided by v where density is 1 .18 for hydrochloric acid, density is equal to 1 .18 gram per milliliter.
02:17
So, putting these values m divided by volume is 10.
02:21
Hence here we can find out the mass of hydrochloric acid is 1 .18 multiplied with 10 is equal to 11 .8 gram of hydrochloric acid...