00:01
Okay, so for this one, if we have systems of equations like this with two equations and two unknowns, i have to find a way to combine them.
00:10
And you can notice that both of them have the ys already isolated, so i'm just going to set them equal to each other by substitution.
00:16
So basically, i'm taking this entire equation and plugging it in for this y over here.
00:22
So now i have x squared plus x plus 6 is equal to 2x squared minus x plus 3.
00:30
So from here i just have to solve, so i'm going to go ahead and get everything on one side of the equation by subtracting an x squared, subtracting an x, and subtracting a 6.
00:39
From both sets of the equation.
00:41
So now i have nothing on the left side, and i have x squared minus 2x, minus 3 on the other side of the equation.
00:50
From here, i'm just going to go ahead and factor it, and then i'm going to get x minus 3 and x plus 1, which means that our xes are 3 and negative 1.
01:02
But i'm not done here because i still have to find out the y's.
01:06
So i just have to plug these back into either of the original equations...