00:01
Hello, in this question, first let us find out the balanced chemical reaction in this case.
00:09
So here if we see that is the cu cl2 and h2o, it is reacting with aluminium and hence it is forming this cu plus alcl3 aluminium chloride plus h2o.
00:30
So if we balance this equation that will become three, two moles of aluminium, three moles of cu and here two moles of alcl3 and 6 moles of h2o.
00:44
So this is the balanced reaction.
00:50
So here now we can find out the total grams of this copper chloride dehydrate and aluminium which is used in this experiment.
01:02
So here as we can see that is the this 3 moles of cocl2 h2 is present here multiply by the molar mass of this cocl2 h2 it is 170 .5 gram so therefore here this will become that is 5111 .5 and that is for aluminium 2 moles of aluminium it is this is for c -u -c -l -2h2o and for aluminium 2 multiply by 27 it is a molar mass of molar mass of aluminum and that will become 54 grams similarly we can find out the rest of the copper for copper this is for aluminium if we need to find out the copper that will be 3 multiply by 63 .5 gram is equal to that that will become 190 .5 gram per copper and similarly we can find out the rest of this here see this molar mass we can molar mass it is the sum of the molar mass of all the elements or all the entities which is present in the molecule so therefore we can say that that is amount of here in this question we are asked amount of c u c l2 h2o here amount which is used it is equal to 511 .5 gram.
02:55
And similarly, this amount of aluminum which is used in this reaction, it is equal to 54 gram.
03:08
This is found by, as we know that, that is number of moles is equal to mass divided by molar mass.
03:18
So therefore we can find out the mass here...