00:03
Hello, for this question we have to find the height of a geostationary satellite, the altitude of the satellite above the earth.
00:14
So this distance is r, the height above the earth is h and the radius of the earth is let's call that capital r.
00:31
So it is clear from this that small r equals h plus capital r.
00:37
Now we use the four edge of stationary satellite or for a satellite, we use the idea that the gravitational force of attraction between the satellite and the head is the source of the centrifugal acceleration that keeps the satellite in orbit.
01:01
So we can cancel this out and we know that angular frequency is given by 2 pi over capital t.
01:09
Capital t is the period of the satellite.
01:13
For a geostationary satellite, the period is 24 hours.
01:17
So that is 24 hours times 3 ,600 seconds.
01:23
So this is 86 ,400.
01:35
So we write this as gm equals w squared, this is squared, sorry, w squared r cubed.
01:51
So gmw is 2 pi over t all squared r cubed.
02:05
So we need to find our r cube...