Question

$f(t) = \begin{cases} \frac{1}{\ln(2)} \frac{1}{t+1} & \text{if } 0 \le t \le 1\\ 0 & \text{otherwise} \end{cases}$

          $f(t) = \begin{cases} \frac{1}{\ln(2)} \frac{1}{t+1} & \text{if } 0 \le t \le 1\\ 0 & \text{otherwise} \end{cases}$

f(t) = (1)/(ln(2))(1)/(t+1) if 0 ≤ t ≤ 1
0 otherwise

Added by Sandra H.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Wei Zhang

Step 1

The given time frame is from 8:10 AM to 8:45 AM, which is a total of 35 minutes or 35/60 = 7/12 hours. Show more…

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Marco is supposed to be at work every weekday morning at 8:30 AM. What is the probability that Marco will be on time if Marco arrives at a time uniformly distributed from 8:10-8:45 AM? 2. Corrected_text: What is the probability that Marco will be on time if Marco arrives at a time T with a probability density function as shown below, where t is the number of hours after 8 AM? f(t) = ln(2)t + 1, if 0 < t < 1 f(t) = 0, otherwise Title_with_topic: Probability of Marco being on time based on arrival time distribution.