00:01
It is given that we have to test the null hypothesis h0 of such that the proportion of color distributed is same as the climbed proportion.
00:17
This is the alternative hypothesis ha of such that at least one color differ from the given climbed.
00:29
Distribution.
00:31
Now for the color of red, yellow, green, blue, orange and brown, the observed values oi are given as 12, 12, 18, 5, 16 and 9 and sum of these values is 72 and the climbed proportion p .i.
01:10
Are given as 0 .12, 0 .15, 0 .15, 0 .2, 0 .15 .0 .2 .0 .2 .0 .0 .2.
01:26
Now, the expected value e .i for each of the color is calculated as.
01:33
As the total value of 72 into the respective proportion pa values.
01:41
Thus the expected values are 8 .64, 10 .8, 10 .8, 16 .56, 16 .56 and 8 .64.
01:59
Now, the value of oi.
02:02
Minus ei, the whole square divided by ei for each of the color are 1 .3067, 0 .1, triple three, 4 .8, 8 .0697, 0 .0 .0 .018, and 0 .015 .0 .015.
02:31
Now, and 0 .015...