Question

Match each of the following with the correct statement. A. The series is absolutely convergent. C. The series converges, but is not absolutely convergent. D. The series diverges. 1. $\sum_{n=1}^{\infty} \frac{sin(6n)}{n^3}$ 2. $\sum_{n=1}^{\infty} (-1)^{n+1} \frac{(7+n)5^n}{(n^2)5^{2n}}$ 3. $\sum_{n=1}^{\infty} \frac{(-5)^n}{n^3}$ 4. $\sum_{n=1}^{\infty} \frac{(n+4)!}{n!3^n}$ 5. $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{4n+5}$

          Match each of the following with the correct statement.
A. The series is absolutely convergent.
C. The series converges, but is not absolutely convergent.
D. The series diverges.
1. $\sum_{n=1}^{\infty} \frac{sin(6n)}{n^3}$
2. $\sum_{n=1}^{\infty} (-1)^{n+1} \frac{(7+n)5^n}{(n^2)5^{2n}}$
3. $\sum_{n=1}^{\infty} \frac{(-5)^n}{n^3}$
4. $\sum_{n=1}^{\infty} \frac{(n+4)!}{n!3^n}$
5. $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{4n+5}$
        
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Match each of the following with the correct statement.
A. The series is absolutely convergent.
C. The series converges, but is not absolutely convergent.
D. The series diverges.
1. ∑n=1^∞(sin(6n))/(n^3)
2. ∑n=1^∞ (-1)^n+1((7+n)5^n)/((n^2)5^2n)
3. ∑n=1^∞((-5)^n)/(n^3)
4. ∑n=1^∞((n+4)!)/(n!3^n)
5. ∑n=1^∞((-1)^n+1)/(4n+5)

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Dinm 723 2.D=1(-1n+1(7+n5 n252n
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Transcript

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00:01 In this question, for each of the given series, we need to determine whether it converges or diverges.
00:05 The first series is sum n is equal to 1 to infinity minus 1 to the whole power n, n power minus 1, i n of n plus 5.
00:15 So it is converges, but it is not absolutely convergent.
00:32 So the answer for this series is c.
00:36 And for the second series, sum n is equal to 1 to infinity minus 2 n the whole power n by n power 6n.
00:47 So this is diverges.
00:50 So the answer is option b.
00:56 And for the third one, it is sum n is equal to 1 to infinity n cube by 2 minus 5n the whole square, the whole power n.
01:10 So this is converges, but it is not absolutely convergent...
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