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Homework: Before next class, match the appropriate temperature to give a spontaneous process ($\Delta G < 0$) under the indicated conditions $\Delta G = \Delta H - T\Delta S$ Conditions Kelvin temperature at which $\Delta G < 0$ 1 $\Delta H > 0$ and $\Delta S > 0$ Any temperature /All temperatures 2 $\Delta H < 0$ and $\Delta S > 0$ $T > \frac{\Delta H}{\Delta S}$ 3 $\Delta H < 0$ and $\Delta S < 0$ $T < \frac{\Delta H}{\Delta S}$

          Homework: Before next class, match the appropriate temperature to give a spontaneous process ($\Delta G < 0$) under the indicated conditions
$\Delta G = \Delta H - T\Delta S$
Conditions
Kelvin temperature at which $\Delta G < 0$
1 $\Delta H > 0$ and $\Delta S > 0$
Any temperature /All temperatures
2 $\Delta H < 0$ and $\Delta S > 0$
$T > \frac{\Delta H}{\Delta S}$
3 $\Delta H < 0$ and $\Delta S < 0$
$T < \frac{\Delta H}{\Delta S}$
        
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Homework: Before next class, match the appropriate temperature to give a spontaneous process (Δ G < 0) under the indicated conditions
Δ G = Δ H - TΔ S
Conditions
Kelvin temperature at which Δ G < 0
1 Δ H > 0 and Δ S > 0
Any temperature /All temperatures
2 Δ H < 0 and Δ S > 0
T > (Δ H)/(Δ S)
3 Δ H < 0 and Δ S < 0
T < (Δ H)/(Δ S)

Added by Amparo B.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Match the appropriate temperature to give a spontaneous process ((Delta G < 0)) under the indicated conditions (Delta G = Delta H - TDelta S) Homework: Before next class, match the appropriate temperature to give a spontaneous process ((G < 0)) under the indicated conditions (G = H - TS) Conditions: Kelvin temperature at which (G < 0) 1. (H > 0) and (S > 0) Any temperature / All temperatures 2. (H < 0) and (S > 0) (T > frac{H}{S}) 3. (H < 0) and (S < 0) (T < frac{H}{S})
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00:01 So twice of n o2 to get n2 o4 so we know that delta g which is equal to delta h minus t into delta s so for the process just spontaneous now this process is just spontaneous delta g which is equal to zero now here delta h which is equal to t delta s okay so here delta h which is equal to minus 56 .8 kilojoule we can write here like…
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