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Hello students.
00:01
So, for this question, we have various solutions and we have to arrange them according to the freezing point.
00:07
So, we will do that using this equation, delta tf is equals to ikfm.
00:13
So, the solvent in all these is the water.
00:17
So, we know that delta tf is tf of solvent minus tf of the solution that is equals to ikfm.
00:28
So, we can say that since solvent is water, this is 0 degree celsius minus tf of solution is equals to ikfm.
00:37
So, we can say that the tf of the solution is equals to minus ikfm.
00:44
So, we will use this formula to calculate the freezing point of various solutions.
00:53
So, the first one that we have with us is 0 .13 molar febr3.
01:00
So, we know that i for this is 3 as it will 4 as it will give 4 ions and we know that the kf of water which will use is 1 .86 degree celsius per molar.
01:13
So, the delta tf will is i.
01:17
So, the first solution we have is 0 .13 molar febr3.
01:27
So, we know that the i for this is 4 as it will give 4 ions.
01:33
Febr3 dissociates to give fe3++3br-.
01:39
So, and the kf which we are going to use is 1 .86 degree celsius per molar.
01:45
So, the tf of febr3 is equals to minus kfm that is equals to minus 4 into 1 .86 into 0 .13 that is minus 0 .9672 degree celsius.
02:08
Then second one we have is 0 .28 molar feso4.
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So, feso4 dissociates to give fe2++so4-.
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So, the i is 2.
02:21
So, the tf for feso4 is equals to minus i kfm.
02:30
So, here the i is 2, kf is 1 .86 and m is 0 .28.
02:35
So, that is equals to minus 1 .042 degree celsius...