00:01
Hello students, let's look at the question.
00:02
So here trial one and trial two, it is already given in the question.
00:05
So if we see the average specific heat.
00:09
So average specific heat is, is 0 .6997.
00:19
9.
00:19
This is average specific heat.
00:22
Then heat gained by weaker q1, sorry, water, q1 is equal to m1c dale t1 and heat k into water q2 is equal to m2 mc m2 c dale t2.
00:48
Now put the values.
00:50
M1 is 19 .795 is multiplied by the value of c that is 4 .186 is multiplied by dl t and dl t is 13 .1 and it is equal to 1085 .49 jule.
01:20
And here for q2, m2 is 19 .891 is multiplied by 4 .186 is multiplied by t2, t2 is 13...