Question

[Maximum mark: 1] Planet X has a gravitational field strength of \( 18 \mathrm{~N} \mathrm{~kg}^{-1} \) at its surface. Planet \( Y \) has the same density as \( X \) but three times the radius of \( X \). What is the gravitational field strength at the surface of \( Y \) ? A. \( 6 \mathrm{~ms}^{-2} \) B. \( 18 \mathrm{~ms}^{-2} \) C. \( 54 \mathrm{~ms}^{-2} \) D. \( 162 \mathrm{~ms}^{-2} \)

          [Maximum mark: 1]
Planet X has a gravitational field strength of \( 18 \mathrm{~N} \mathrm{~kg}^{-1} \) at its surface. Planet \( Y \) has the same density as \( X \) but three times the radius of \( X \). What is the gravitational field strength at the surface of \( Y \) ?
A. \( 6 \mathrm{~ms}^{-2} \)
B. \( 18 \mathrm{~ms}^{-2} \)
C. \( 54 \mathrm{~ms}^{-2} \)
D. \( 162 \mathrm{~ms}^{-2} \)

[Maximum mark: 1]
Planet X has a gravitational field strength of 18 N kg^-1 at its surface. Planet Y has the same density as X but three times the radius of X. What is the gravitational field strength at the surface of Y ?
A. 6 ms^-2
B. 18 ms^-2
C. 54 ms^-2
D. 162 ms^-2

Added by Anne G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dharmendra Maheshwari

Step 1

Step 1: Recall the formula for gravitational field strength \( g \) at the surface of a planet: \[ g = \frac{G M}{R^2} \] where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet. Show more…

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[Maximum mark: 1] Planet X has a gravitational field strength of \( 18 \mathrm{~N} \mathrm{~kg}^{-1} \) at its surface. Planet \( Y \) has the same density as \( X \) but three times the radius of \( X \). What is the gravitational field strength at the surface of \( Y \) ? A. \( 6 \mathrm{~ms}^{-2} \) B. \( 18 \mathrm{~ms}^{-2} \) C. \( 54 \mathrm{~ms}^{-2} \) D. \( 162 \mathrm{~ms}^{-2} \)