00:01
In this problem, you're getting four fisher projections, and you're asked which of these are anantumurs.
00:07
So, first of all, remember, anantumers are going to have opposite stereocentors, so if one has r, the other is s.
00:14
Here we have two stereocentors, so we're looking at, if we had rs for one, we have sr for the other.
00:23
So we're just going to keep reversing it, and they should be opposites.
00:27
So if we look here, notice that in our top two, bromine and chlorine are on different sides, whereas down here, they're on the same side.
00:38
So right away, we can determine that one and two are going to be different than three and four.
00:51
So we can just compare now one and two to each other and three and four to each other.
00:58
And if we start with one and two, bromine has top priority.
01:04
This carbon has a chlorine, so it would be second priority.
01:08
This will be third.
01:11
Here, we go in counterclockwise direction, so you think s.
01:16
But hydrogen is in front of the plane.
01:19
So this gives us r.
01:22
If we check over here, because this is going to be the same carbon as this, we're going to have our priorities again.
01:37
But here, notice that the carbon attached to our ethyl group has bermine instead of chlorine...