00:01
Hello students, in this question we are asked to calculate moment of inertia i for hcn molecule and also we need to calculate the rotational constant b.
00:12
The solution is as follows.
00:14
First we need to have bond lengths and masses of atoms.
00:18
Bond length of hc bond is 1 .06 angstrom, bond length for cn bond is 1 .16 angstrom, mass of 1h is 1 .67 into 10 power minus 27 kg, mass of c12 is 1 .99 into 10 power minus 26 kg, mass of n14 is 2 .32 into 10 power minus 26 kg.
00:41
This bond length and masses value are constant values.
00:46
Next we need to convert bond length to meters that is 1 .06 angstrom to 1 .06 into 10 power minus 10 meters.
00:59
Similarly 1 .16 angstrom equals 1 .16 into 10 to the power minus 10 meter.
01:07
Next we have to calculate moment of inertia.
01:10
Moment of inertia i is given by mu into r square where mu is the reduced mass, r is the distance between the atoms.
01:19
Now for a linear rotor like hcn, moment of inertia is given as the sum of moments of inertia for hc bond and cn bond that is i equal to mh into mc divided by mh plus mc into rhc square plus mc into mn divided by mc plus mn into rcn square.
01:43
Now plugging the values and calculating i, we have i equals 1 .67 into 10 to the power minus 27 kg into 1 .99 into 10 power minus 26 kg divided by 1 .67 into 10 to the power minus 27 plus 1 .99 into 10 to the power minus 26 kg into 1 .06 into 10 to the power minus 10 meter square plus 1 .99 into 10 to the power minus 26 kg into 2 .32 into 10 to the power minus 26 kg divided by 1 .99 into 10 to the power minus 26 plus 2 .32 into 10 to the power minus 26 kg into 1 .16 into 10 to the power minus 10 meter square.
02:56
Now on solving we get moment of inertia i approximately equal to 2 .33 into 10 to the power minus 46 kg meter square.
03:14
We got moment of inertia.
03:16
Now we have to calculate the rotational constant b...