00:01
In this question, we have been given gear ratio that is n is equal to 9 and the gear speed is equal to 2500 rpm and the diameter d is equal to 0 .62 meter and we need to find the acceleration.
00:27
So first of all we will calculate wheel rotational speed which is n and this is equal to the gear speed that is 25 divided by the gear ratio that is 9.
00:45
So this is also in rpm.
00:48
Now the bike speed is equal to pi times diameter times rotational speed divided by 60.
00:58
So this will be pi times 0 .62 multiplied by 2500 divided by 9 and then whole divided by 60 and this will be in meter per second.
01:10
So if we solve this we will get this velocity or you can say the bike speed is equal to 9 .016 meter per second.
01:21
Now let's convert this speed into kilometer per hour and this will be 32 .5 kilometer per hour.
01:31
Now we will find equivalent moment of inertia that is i equivalent and this is equal to twice the moment of inertia of wheel plus n squared that is gear ratio squared times moment of inertia of gear plus md squared divided by 4 that is m here is the mass of bike.
02:05
So now let's find i equivalent and this is equal to 2 times 1 plus 9 squared multiplied by 0 .2 plus the mass is 200 multiplied by 0 .31 whole squared.
02:27
So on solving this we will get i equivalent equal to 37 .42 kg meter squared.
02:36
So we have calculated this equivalent moment of inertia.
02:40
Now torque t is equal to force multiplied by d divided by 2...