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Assignment 1 of chapter 5 The figure below shows a cantilever beam with rectangular sections, and it is subjected to two concentrated loads F1 and F2, F1=2F2=5kN. Try to determine the maximum normal stress in the beam and the normal stress at point K on the section where the stress is located

          Assignment 1 of chapter 5
The figure below shows a cantilever beam with rectangular sections, and it is subjected to
two concentrated loads F1 and F2, F1=2F2=5kN. Try to determine the maximum normal
stress in the beam and the normal stress at point K on the section where the stress is
located
        
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Assignment 1 of chapter 5
The figure below shows a cantilever beam with rectangular sections, and it is subjected to
two concentrated loads F1 and F2, F1=2F2=5kN. Try to determine the maximum normal
stress in the beam and the normal stress at point K on the section where the stress is
located

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Mechanics of Materials Assignment 1 of Chapter 5 The figure below shows a cantilever beam with rectangular sections, and it is subjected to two concentrated loads F1 and F2, where Fi = 2F2 - 5 kN. Try to determine the maximum normal stress in the beam and the normal stress at point K on the section where the stress is located. F2 Im Im
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A cantilever beam of rectangular cross section is subjected to a concentrated load P = 150 kN acting at the free end (see Figure 1). The beam has width b = 80 mm. and height h = 260 mm. Point A is located at distance c = 0.5 m from the free end and distance d = 220 mm. from the bottom of the beam. a) Using Mohr's circle, calculate the principal stresses σ1 and σ2 and the maximum shear stress τmax at point A. b) Show these stresses on sketches of properly oriented elements. Figure 1: A cantilever beam

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Transcript

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00:01 So, it is given that ina is equal to 981 .3 in to the power 4 and wo is given as 300 of lb divided by feet and p value is given as 2 of lb and the sigma of max is given as 1400 psi.
00:24 So basically, here we have this is r1 and this is r2 and let us say it that anv.
00:36 Let us name that this is a and this is b and this is c.
00:41 From here it is c.
00:43 So, here it is plb with this w here and from here to here it is 9 and from here to here it is 12 inch.
00:53 So, from side bending moment diagram, we can see that the maximum moment occurs under the point of load that is summation of ma will be equal to 0.
01:04 So, r2 which is multiplied by 12 will be equal to p which is multiplied by a plus w which is multiplied by 12 square divided by 2.
01:16 So, this will be 12 of r2 which will be equal to 9p plus 300 which is multiplied by 12 square divided by 2.
01:24 Here we have r2 will be equal to 1800 plus 0 .75 of p...
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