Question

How much energy is involved (magnitude only) when 10500 H+ ions move across a membrane with a Nernst potential of $\Delta V = 50 mV$ (please use electron-Volts for your answer)? Remember, the Boltzmann probability factor: $Z = e^{-\frac{\Delta E}{k_B T}}$, Boltzmann's constant is $k_B = 1.38 \times 10^{-23} \frac{J}{K}$, and the charge on a proton is $e = + 1.6 \times 10^{-19} C$. Express your answer as a multiple of the energy unit electron-Volt (eV) where $1 eV = 1.6 \times 10^{-19} Joules$ which is the energy it takes one electron to move through a voltage difference of 1 Volt.

          How much energy is involved (magnitude only) when 10500 H+ ions move across a membrane with a Nernst potential of $\Delta V = 50 mV$ (please use electron-Volts for your answer)? Remember, the Boltzmann probability factor: $Z = e^{-\frac{\Delta E}{k_B T}}$, Boltzmann's constant is $k_B = 1.38 \times 10^{-23} \frac{J}{K}$, and the charge on a proton is $e = + 1.6 \times 10^{-19} C$. Express your answer as a multiple of the energy unit electron-Volt (eV) where $1 eV = 1.6 \times 10^{-19} Joules$ which is the energy it takes one electron to move through a voltage difference of 1 Volt.

How much energy is involved (magnitude only) when 10500 H+ ions move across a membrane with a Nernst potential of Δ V = 50 mV (please use electron-Volts for your answer)? Remember, the Boltzmann probability factor: Z = e^-(Δ E)/(kB T), Boltzmann's constant is kB = 1.38 × 10^-23(J)/(K), and the charge on a proton is e = + 1.6 × 10^-19 C. Express your answer as a multiple of the energy unit electron-Volt (eV) where 1 eV = 1.6 × 10^-19 Joules which is the energy it takes one electron to move through a voltage difference of 1 Volt.

Added by Jacqueline V.

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