Merrill Kim Sharp has a system composed of three components in parallel. The components have the following reliabilities: $R_1 = 0.89$, $R_2 = 0.92$, and $R_3 = 0.81$. The overall reliability of the system = % (enter your response as a percentage rounded to two decimal places).
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Substituting the given values, we get: Roverall = 1 - (1 - 0.89) x (1 - 0.92) x (1 - 0.81) Roverall = 1 - (0.11 x 0.08 x 0.19) Roverall = 1 - 0.001672 Roverall = 0.998328 To convert this to a percentage, we multiply by 100: Roverall = 99.8328% Show more…
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