Metallic zinc reacts with aqueous iron(III) nitrate to form metallic iron and aqueous zinc(II) nitrate. If 46.5 g of zinc are added to 600 mL of 1.00 M iron(III) nitrate how many g of metallic iron will be formed? 18.2 g 26.5 g 22.4 g none of the answers are correct
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Zinc reacts with iron(III) nitrate to produce iron and zinc nitrate. The balanced equation is: \[ \text{Zn (s)} + \text{2Fe(NO}_3\text{)}_3 \text{ (aq)} \rightarrow \text{2Fe (s)} + \text{3Zn(NO}_3\text{)}_2 \text{ (aq)} \] Show more…
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