00:01
Okay, so here we have methane gas, reacting with chlorine gas, to make hydrogen chloride gas and carbon tetrachloride gas.
00:13
So first we want to go ahead and balance this.
00:15
So to balance the chlorines, we can put a two here.
00:22
Or actually, hold on.
00:23
We have five chlorines on the right side and only two in the left.
00:28
So that means we need to find a common multiplier between them.
00:32
But let's see if we can balance some other things first and see if that helps.
00:36
So carbons look balanced, but the hydrogens are not.
00:39
So we can put a four here to balance the hydrogens.
00:42
So four on each side now, one carbon on each side.
00:46
And now the chlorine's on the right side, we have eight.
00:49
And so now we can put a four here so that the chlorines are balanced as well.
00:53
So we want to know what volume of hydrogen chloride would be produced if 1 .72 cubic centimeters of chlorine were consumed.
01:03
So what we can do, we can assume this is at stp.
01:07
And so at stp, 22 .4 liters is equal to one mole.
01:15
And so what we can do is we can use that to get into units of moles and then use a molar ratio in our equation to get from reactants to products and then convert it back into a volume...